Balbharati Maharashtra State Board11th Commerce Maths Solution Book PdfChapter 4 Sequences and Series Ex 4.1 Questions and Answers.
Maharashtra State Board 11th Commerce Maths Solutions Chapter 4 Sequences and Series Ex 4.1
Solution & Step-by-Step Answer:
(i) 2, 6, 18, 54, ……. t1 = 2, t2 = 6, t3 = 18, t4 = 54, ….. Here, Since, the ratio of any two consecutive terms is a constant, the given sequence is a geometric progression. Here, a = 2, r = 3 tn= arn-1 ∴ tn = 2(3n-1)
(ii) 1, -5, 25, -125, ……
t1= 1, t2= -5, t3= 25, t4= -125, …..
Here,
Since, the ratio of any two consecutive terms is a constant, the given sequence is a geometric progression.
Here, a = 1, r = -5
tn= arn-1
∴ tn= (-5)n-1
(iii)
Since, the ratio of any two consecutive terms is a constant, the given sequence is a geometric progression.


(iv) 3, 4, 5, 6,……
t1= 3, t2= 4, t3= 5, t4= 6, …..
Here,
Since,
∴ the given sequence is not a geometric progression.
(v) 7, 14, 21, 28, …..
t1= 7, t2= 14, t3= 21, t4= 28, …..
Here,
Since,
∴ the given sequence is not a geometric progression.
Solution & Step-by-Step Answer:


Solution & Step-by-Step Answer:

Solution & Step-by-Step Answer:

Solution & Step-by-Step Answer:
The sequence (tn) is a G.P., if = constant, for all n ∈ N ∴ the sequence is a G. P. with common ratio First term, t1 =

Solution & Step-by-Step Answer:
Let the three numbers in G. P. be , a, ar. According to the first condition, ∴ the three numbers are 12, 6, 3 or 3, 6, 12. Check: First condition: 12, 6, 3 are in G.P. with r = 12 + 6 + 3 = 21 Second condition: 122 + 62 + 32 = 144 + 36 + 9 = 189 Thus, both the conditions are satisfied.



Solution & Step-by-Step Answer:
Let the four numbers in G.P. be . According to the second condition, ∴ a4 = 1 ∴ a = 1 According to the first condition,

Solution & Step-by-Step Answer:
Let the five numbers in G. P. be According to the given conditions, When a = 4, r = -2 = 1, = -2, a = 4, ar = -8, ar2 = 16 ∴ the five numbers in G.P. are 1, 2, 4, 8, 16 or 1, -2, 4, -8, 16.

Solution & Step-by-Step Answer:

Solution & Step-by-Step Answer:
p, q, r, s are in G.P. ∴ p + q, q + r, r + s are in G.P.
