Maharashtra State Board 11th Maths Solutions Chapter 4 Methods of Induction and Binomial Theorem Ex 4.4
Question 1
Maharashtra Board Solution
State, by writing the first four terms, the expansion of the following, where |x| < 1. (i) (1 + x)-4
Solution & Step-by-Step Answer:
(ii) (1 – x)1/3
Solution:
(iii) (1 – x2)-3
Solution:
(iv) (1 + x)-1/5
Solution:
(v) (1 + x2)-1
Solution:
Question 2
Maharashtra Board Solution
State by writing first four terms, the expansion of the following, where |b| < |a|. (i) (a – b)-3
Solution & Step-by-Step Answer:
(a – b)-3 =
(ii) (a + b)-4
Solution:
(iii) (a + b)1/4
Solution:
(iv) (a – b)-1/4
Solution:
(a – b)-1/4=
(v) (a + b)-1/3
Solution:
Question 3
Maharashtra Board Solution
Simplify the first three terms in the expansion of the following: (i) (1 + 2x)-4
Solution & Step-by-Step Answer:
(ii) (1 + 3x)-1/2
Solution:
(iii) (2 – 3x)1/3
Solution:
(iv) (5 + 4x)-1/2
Solution:
(v) (5 – 3x)-1/3
Solution:
Question 4
Maharashtra Board Solution
Use the binomial theorem to evaluate the following upto four places of decimals. (i) √99
Solution & Step-by-Step Answer:
= 10 [1 – 0.005 – 0.0000125 – ……] = 10(0.9949875) = 9.94987 5 = 9.9499
(ii)
Solution:
(iii)
Solution:
(iv) (1.02)-5
Solution:
(v) (0.98)-3
Solution:
