Maharashtra State Board 11th Maths Solutions Chapter 8 Measures of Dispersion Ex 8.2
Question 1
Maharashtra Board Solution
Find variance and S.D. for the following set of numbers. 7, 11, 2, 4, 9, 6, 3, 7, 11, 2, 5, 8, 3, 6, 8, 8, 2, 6
Solution & Step-by-Step Answer:
Given data: 7, 11, 2, 4, 9, 6, 3, 7, 11, 2, 5, 8, 3, 6, 8, 8, 2, 6 The tabulated form of the above data is Calculation of variance and S.D.



Question 2
Maharashtra Board Solution
Find variance and S.D. for the following set of numbers. 65, 77, 81, 98, 100, 80, 129
Solution & Step-by-Step Answer:

Question 3
Maharashtra Board Solution
Compute variance and standard deviation for the following data:
Solution & Step-by-Step Answer:



Question 4
Maharashtra Board Solution
Compute the variance and S.D.
Solution & Step-by-Step Answer:
Let u = Calculation of variance of u:


Question 5
Maharashtra Board Solution
Following data gives ages of 100 students in a college. Calculate variance and S.D.
Solution & Step-by-Step Answer:
Let u =



Question 6
Maharashtra Board Solution
Find mean, variance and S.D. of the following data.
Solution & Step-by-Step Answer:
Alternate Method: Let u = Calculation of variance of u:





Question 7
Maharashtra Board Solution
Find the variance and S.D. of the following frequency distribution which gives the distribution of 200 plants according to their height.
Solution & Step-by-Step Answer:
Since data is not continuous, we have to make it continuous. Let u = Calculation of variance of u:



Question 8
Maharashtra Board Solution
The mean of 5 observations is 4.8 and the variance is 6.56. If three of the five observations are 1, 3, and 8, find the other two observations.
Solution & Step-by-Step Answer:
= 4.8, Var (X) = 6.56, n = 5, x1 = 1, x2 = 3, x3 = 8 ……(given) Let the remaining two observations be x4 and x5. From (i), we get x5 = 5 or x5 = 7 ∴ The two numbers are 5 and 7.

