Latest Maharashtra State Board (SSC & HSC) 2026-27 Syllabus Digest & Solutions Updated!
Class 12 (HSC Board)Commerce Mathematics & Statistics2026-27 Syllabus

Chapter 5 Integration Miscellaneous Exercise 5 Solutions

Complete Maharashtra State Board Balbharati & Yuvakbharati textbook solutions for Chapter 5 Integration Miscellaneous Exercise 5. Step-by-step solved exercises, numerical problems, and digest answers.

20 Solved Questions37 Diagrams717 words

Balbharati Maharashtra State BoardStd 12 Commerce Statistics Part 1 Digest PdfChapter 5 Integration Miscellaneous Exercise 5 Questions and Answers.

Maharashtra State Board 12th Commerce Maths Solutions Chapter 5 Integration Miscellaneous Exercise 5

(I) Choose the correct alternative from the following:

Question 1 Maharashtra Board Solution
The value of is (a) 20 + c (b) -2 + c (c) √x + c (d) x + c
Solution & Step-by-Step Answer:
(b) -2 + c
Question 2 Maharashtra Board Solution
= (a) (b) (c) (d)
Solution & Step-by-Step Answer:
(a)
Question 3 Maharashtra Board Solution
= (a) (b) (c) (d)
Solution & Step-by-Step Answer:
(b) Hint: Put x3 = t
Question 4 Maharashtra Board Solution
+ , then p = __________ (a) (b) (c) (d) 2
Solution & Step-by-Step Answer:
(c) Hint:
Question 5 Maharashtra Board Solution
= ________ (a) log x – log(1 – x) + c (b) log(1 – x2) + c (c) -log x + log(1 – x) + c (d) log(x – x2) + c
Solution & Step-by-Step Answer:
(a) log x – log(1 – x) + c
Question 6 Maharashtra Board Solution
= __________ (a) (b) (c) (d) (x – 8)(x – 7) + c
Solution & Step-by-Step Answer:
(c)
Question 7 Maharashtra Board Solution
= _________ (a) (b) (c) (d)
Solution & Step-by-Step Answer:
(b) Hint:
Question 8 Maharashtra Board Solution
(a) (b) (c) (d)
Solution & Step-by-Step Answer:
(a)
Question 9 Maharashtra Board Solution
∫(1 – x)-2 dx = ___________ (a) (1 + x)-1 + c (b) (1 – x)-1 + c (c) (1 – x)-1 – 1 + c (d) (1 – x)-1 + 1 + c
Solution & Step-by-Step Answer:
(b) (1 – x)-1 + c
Question 10 Maharashtra Board Solution
= _______ (a) (b) (c) log(x + 1) + c (d) log|x + 1|5 + c
Solution & Step-by-Step Answer:
(a) Hint: x3 + 3x2 + 3x + 1 = (x + 1)3

(II) Fill in the blanks.

Question 1 Maharashtra Board Solution
dx = x4 + ___x3 + 5x + c.
Solution & Step-by-Step Answer:
Hint: x6 + 1 = (x2 + 1)(x4 – x2 + 1)
Question 2 Maharashtra Board Solution
= x + ______ + c
Solution & Step-by-Step Answer:
4 log|x – 1| Hint: x2 + x – 6 = (x + 3)(x – 2)
Question 3 Maharashtra Board Solution
If f'(x) = + x and f(1) = then f(x) = log x + + _______
Solution & Step-by-Step Answer:
2 Hint:

Question 4 Maharashtra Board Solution
To find the value of the proper substitution is __________
Solution & Step-by-Step Answer:
1 + log x = t
Question 5 Maharashtra Board Solution
= p(log x)3 + c, then p = _______
Solution & Step-by-Step Answer:
Hint:

(III) State whether each of the following is True or False:

Question 1 Maharashtra Board Solution
The proper substitution for
Solution & Step-by-Step Answer:
True
Question 2 Maharashtra Board Solution
If ∫x e2x dx is equal to e2x f(x) + c where c is constant of integration, then f(x) is .
Solution & Step-by-Step Answer:
False
Question 3 Maharashtra Board Solution
If ∫x f(x) dx = , then f(x) = .
Solution & Step-by-Step Answer:
True
Question 4 Maharashtra Board Solution
If = A log|x + 1| + B log|x – 2|, then A + B = 1.
Solution & Step-by-Step Answer:
True
Question 5 Maharashtra Board Solution
For = ex f(x) + c, f(x) = (x + 1)2.
Solution & Step-by-Step Answer:
False

(IV) Solve the following:

1. Evaluate:

(i)
Solution:

(ii)
Solution:

(iii)
Solution:

(iv)
Solution:

(v) If f'(x) = √x and f(1) = 2, then find the value of f(x).
Solution:
By the definition of integral

(vi) ∫|x| dx if x < 0
Solution:
∫|x| dx = ∫-x dx …..[∵ x < 0]
= -∫x dx
= + c

2. Evaluate:

(i) Find the primitive of
Solution:
Let I be the primitive of

(ii)
Solution:

(iii)
Solution:

(iv)
Solution:

(v)
Solution:

3. Evaluate:

(i)
Solution:

(ii)
Solution:

(iii)
Solution:

(iv)
Solution:

(v)
Solution:

(vi)
Solution:

(vii)
Solution:

(viii)
Solution:

4. Evaluate:

(i) ∫(log x)2dx
Solution:

(ii)
Solution:

(iii) ∫x e2xdx
Solution:

(iv) ∫log(x2+ x) dx
Solution:

(v)
Solution:

(vi)
Solution:

(vii)
Solution:

5. Evaluate:

(i)
Solution:

(ii)
Solution:


(iii)
Solution: