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Class 6Mathematics & Statistics2026-27 Syllabus

Chapter 5 Decimal Fractions Practice Set 17 Solutions

Complete Maharashtra State Board Balbharati & Yuvakbharati textbook solutions for Chapter 5 Decimal Fractions Practice Set 17. Step-by-step solved exercises, numerical problems, and digest answers.

5 Solved Questions429 words

6th Standard Maths Practice Set 17 Answers Chapter 5 Decimal Fractions

Question 1 Maharashtra Board Solution
Carry out the following divisions. i. 4.8÷2 ii. 17.5÷5 iii. 20.6÷2 iv. 32.5÷25
Solution & Step-by-Step Answer:
i. 4.8÷2

ii. 17.5÷5

iii. 20.6÷2

iv. 32.5÷25

Question 2 Maharashtra Board Solution
A road is 4 km 800 m long. If trees are planted on both its sides at intervals of 9.6 m, how many trees were planted?
Solution & Step-by-Step Answer:
Length of road = 4 km 800 m = 4 × 1000 m + 800 m = 4000 m + 800 m = 4800 m Number of trees on one side = 4800 ÷ 9.6 = 500 ∴ Number of trees on both sides = 2 x number of trees on one side = 2 x 500 = 1000 If the trees are planted at the beginning of the road, then Total number of trees = 1000 + 2 = 1002 ∴ Total number of trees planted is 1000 or 1002.
Question 3 Maharashtra Board Solution
Pradnya exercises regularly by walking along a circular path on a field. If she walks a distance of 3.825 km in 9 rounds of the path, how much does she walk in one round?
Solution & Step-by-Step Answer:
Total distance walked in 9 rounds = 3.825 km ∴Distance walked in 1 round = 3.825 4 ÷ 9 = 0.425 km ∴ Total distance walked in 1 round is 0.425 km.
Question 4 Maharashtra Board Solution
A pharmaceutical manufacturer bought 0.25 quintal of hirada, a medicinal plant, for Rs 9500. What is the cost per quintal of hirada? (1 quintal = 100 kg)
Solution & Step-by-Step Answer:
Cost of 0.25 quintal of hirada = Rs 9500 ∴ Cost of 1 quintal of hirada = 9500 ÷ 0.25 = Rs 38,000 ∴ Cost per quintal of hirada is Rs 38,000.

Maharashtra Board Class 6 Maths Chapter 4 Operations on Fractions Practice Set 17 Intext Questions and Activities

Question 1 Maharashtra Board Solution
Maths is fun! (Textbook pg. no. 34)

Take two or three other numbers. Do the same multiplication and find out how it is done.

Solution & Step-by-Step Answer:
7 × 13 × 11 = 1001
∴ 527 × 1001 = 527 × (1000+ 1)
= (527 × 1000) + (527 × 1)
= 527000 + 527 = 527527
Thus, when any three-digit number is multiplied with 1001, the product obtained is a six-digit number in which the original three-digit number is written back to back twice.
(Students may consider any other three-digit numbers and verify the property.)