Maharashtra State Board Class 7 Mathematics & Statistics Solutions Chapter 14 Algebraic Formulae – Expansion of Squares Practice Set 51 - Digest Answers | Maharashtra Board Solutions

Algebraic Formulae – Expansion of Squares Class 7 Practice Set 51 Answers Solutions Chapter 14

Question 1 Maharashtra Board Solution

Use the formula to multiply the following: i. (x + y)(x – y) ii. (3x – 5)(3x + 5) iii. (a + 6)(a – 6) iv.

Solution & Step-by-Step Answer:

i. Here, a = x, b = y (x + y)(x – y) = x² – y² …. [(a + b)(a – b) = a² – b²]

ii. Here, a = 3x, b = 5
(3x – 5) (3x + 5) = (3x)² – 5²
…. [(a + b)(a – b) = a² – b²]
= 9x² – 25

iii. Here, A = a, B = 6
(a + 6) (a – 6) = a² – 6²
…. [(A + B)(A – B) = A² – B²]
= a² – 36

iv. Here, a = , b = 6

…. [(a + b)(a – b) = a² – b²]
=

Question 2 Maharashtra Board Solution

Use the formula to find the values: i. 502 × 498 ii. 97 × 103 iii. 54 × 46 iv. 98 × 102

Solution & Step-by-Step Answer:

i. 502 × 498 = (500 + 2) (500 – 2) Here, a = 500, b = 2 ∴ (500 + 2) (500 – 2) = 500² – 2² …. [(a + b)(a – b) = a² – b²] = 250000 – 4 = 249996 ∴ 502 × 498 = 249996

ii. 97 × 103 = (100 – 3) (100 + 3)
Here, a = 100, b = 3
∴ (100 – 3) (100 + 3) = 100² – 3²
…. [(a + b)(a – b) = a² – b²]
= 10000 – 9
= 9991
∴ 97 × 103 = 9991

iii. 54 × 46 = (50 + 4) (50 – 4)
Here, a = 50, b = 4
∴ (50 + 4) (50 – 4) = 50² – 4²
…. [(a + b)(a – b) = a² – b²]
= 2500 – 16 = 2484
∴ 54 × 46 = 2484

iv. 98 × 102 = (100 – 2) (100 + 2)
Here, a = 100, b = 2
∴ (100 – 2) (100 + 2) = 100² – 2²
…. [(a + b)(a – b) = a² – b²]
= 10000 – 4
= 9996
∴ 98 × 102 = 9996

Chapter 14 Algebraic Formulae – Expansion of Squares Practice Set 51 Solutions