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Class 9 (SSC)Mathematics & Statistics2026-27 Syllabus

Chapter 4 Ratio and Proportion Practice Set 4.4 Solutions

Complete Maharashtra State Board Balbharati & Yuvakbharati textbook solutions for Chapter 4 Ratio and Proportion Practice Set 4.4. Step-by-step solved exercises, numerical problems, and digest answers.

3 Solved Questions306 words

Practice Set 4.4 Algebra 9th Std Maths Part 1 Answers Chapter 4 Ratio and Proportion

Question 1 Maharashtra Board Solution
Fill in the blanks of the following.
Solution & Step-by-Step Answer:
Question 2 Maharashtra Board Solution
5m – n = 3m + 4n, then find the values of the following expressions.
Solution & Step-by-Step Answer:
5m – n = 3m + 4n … [Given] ∴ 5m – 3m = 4n + n ∴ 2m = 5n
Question 3 Maharashtra Board Solution
Solve: i. If a(y + z) = b(z + x) = c(x + y) and out of a, b, c no two of them are equal, then show that, .
Solution & Step-by-Step Answer:
Here, no two of a, b and c are equal. ∴ values of (b – c), (c – a) and (a – b) are not zero. a(y + z) = b(z + x) = c(x + y) … [Given]

ii. If and x + y + z ≠ 0, then show that the value of each ratio is equal to 1.
Solution:

iii. and x + y + z ≠ 0,then show that .
Solution:

iv. If , then show that .
Solution:

v. If , then show that every ratio = .
Solution:

Ratio And Proportion Class 9 Practice Set 4.4 Question 4.
Solve:

Solution:


∴ 7(4x – 5)3(2x + 3)
∴ 28x – 35 = 6x + 9
∴ 28x – 6x = 9 + 35
∴ 22x = 44
∴ x = 2
∴ x = 2 is the solution of the given equation.

ii.


∴ y + 8 = 3(1 + 2y)
∴ y + 8 = 3 + 6y
∴ 8 – 3 = 6y – y
∴ 5 = 5y
∴ y = 1
∴ y = 1 is the solution of the given equation.