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Class 9 (SSC)Mathematics & Statistics2026-27 Syllabus

Chapter 7 Co-ordinate Geometry Practice Set 7.2 Solutions

Complete Maharashtra State Board Balbharati & Yuvakbharati textbook solutions for Chapter 7 Co-ordinate Geometry Practice Set 7.2. Step-by-step solved exercises, numerical problems, and digest answers.

12 Solved Questions1413 words

Practice Set 7.2 Geometry 9th Std Maths Part 2 Answers Chapter 7 Co-ordinate Geometry

Question 1 Maharashtra Board Solution
On a graph paper plot the points A(3, 0), B(3, 3), C(0, 3). Join A, B and B, C. What is the figure formed? Soiution: d(O, A) = 3 cm, d(A, B) = 3 cm, d(B, C) = 3 cm, d(O, C) = 3 cm and each angle of □ OABC is 90° ∴ □ OABC is a square.

Question 2 Maharashtra Board Solution
Write the equation of the line parallel to the Y-axis at a distance of 7 units from it to its left.
Solution & Step-by-Step Answer:
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Solution & Step-by-Step Answer:
The equation of a line parallel to the Y-axis is x = a. Since, the line is at a distance of 7 units to the left of Y-axis, ∴ a = -7 ∴ x = -1 is the equation of the required line.
Question 3 Maharashtra Board Solution
Write the equation of the line parallel to the X-axis at a distance of 5 units from it and below the X-axis.
Solution & Step-by-Step Answer:
The equation of a line parallel to the X-axis is y = b. Since, the line is at a distance of 5 units below the X-axis. ∴ b = -5 ∴ y = -5 is the equation of the required line.
Question 4 Maharashtra Board Solution
The point Q( -3, -2) lies on a line parallel to the Y-axis. Write the equation of the line and draw its graph.
Solution & Step-by-Step Answer:
The equation of a line parallel to the Y-axis is x = a. Here, a = -3 ∴ x = -3 is the equation of the required line.
Question 5 Maharashtra Board Solution
Y-axis and line x = – 4 are parallel lines. What is the distance between them?
Solution & Step-by-Step Answer:
Equation of Y-axis is x = 0. Equation of the line parallel to the Y-axis is x = – 4. … [Given] ∴ Distance between the Y-axis and the line x = – 4 is 0 – (- 4) … [0 > -4] = 0 + 4 = 4 units ∴ The distance between the Y-axis and the line x = – 4 is 4 units. [Note: The question is modified as X-axis cannot be parallel to the line x = – 4.]
Question 6 Maharashtra Board Solution
Which of the equations given below have graphs parallel to the X-axis, and which ones have graphs parallel to the Y-axis? [1 Mark each] i. x = 3 ii. y – 2 = 0 iii. x + 6 = 0 iv. y = -5
Solution & Step-by-Step Answer:
i. The equation of a line parallel to the Y-axis is x = a. ∴ The line x = 3 is parallel to the Y-axis.

ii. y – 2 = 0
∴ y = 2
The equation of a line parallel to the X-axis is y = b.
∴ The line y – 2 = 0 is parallel to the X-axis.

iii. x + 6 = 0
∴ x = -6
The equation of a line parallel to the Y-axis is x = a.
∴ The line x + 6 = 0 is parallel to the Y-axis.

iv. The equation of a line parallel to the X-axis is y = b.
∴ The line y = – 5 is parallel to the X-axis.

Question 7 Maharashtra Board Solution
On a graph paper, plot the points A(2, 3), B(6, -1) and C(0, 5). If these points are collinear, then draw the line which includes them. Write the co-ordinates of the points at which the line intersects the X-axis and the Y-axis.
Solution & Step-by-Step Answer:
From the graph, the line drawn intersects the X-axis at D(5, 0) and the Y-axis at C(0, 5).
Question 8 Maharashtra Board Solution
Draw the graphs of the following equations on the same system of co-ordinates. Write the co-ordinates of their points of intersection. x + 4 = 0, y – 1 = 0, 2x + 3 = 0, 3y – 15 = 0
Solution & Step-by-Step Answer:
i. x + 4 = 0 ∴ x = – 4

ii. y – 1 = 0
∴ y = 1

iii. 2x + 3 = 0
∴2x = -3
∴ x =
∴ x = -1.5

iv. 3y- 15 = 0
3y = 15
y =
∴ y = 5

The co-ordinates of the point of intersection of x + 4 = 0 and y – 1 = 0 are A(-4, 1).
The co-ordinates of the point of intersection ofy – 1 = 0 and 2x + 3 = 0 are B(-1.5, 1).
The co-ordinates of the point of intersection of 3y – 15 = 0 and 2x + 3 = 0 are C(-1.5, 5).
The co-ordinates of the point of intersection of x + 4 = 0 and 3y – 15 = 0 are D(-4, 5).

Question 9 Maharashtra Board Solution
Draw the graphs of the equations given below. i. x + y = 2 ii. 3x – y = 0 iii. 2x + y = 1
Solution & Step-by-Step Answer:
i. x + y = 2 ∴ y = 2 – x When x = 0, y = 2 – x = 2 – 0 = 2 When x = 1, y = 2 – x = 2 – 1 = 1 When x = 2, y = 2 – x = 0

ii. 3x – y = 0
∴ y = 3x
When x = 0,
y = 3x
= 3(0)
= 0

When x = 1,
y = 3x
= 3(1)
= 3

When x = -1,
y = 3x
= 3(-1)
= -3

iii. 2x + y = 1
∴ y = 1 – 2x
When x = 0,
y = 1 – 2x
= 1 – 2(0)
= 1 – o
When x = 1,
y = 1 – 2x
= 1- 2(1)
= 1 – 2
= -1
When x = -1,
y = 1 – 2x
= 1 – 2(-1)
= 1 + 2
= 3

Maharashtra Board Class 9 Maths Chapter 7 Co-ordinate Geometry Practice Set 7.2 Intext Questions and Activities

Question 1 Maharashtra Board Solution
i. Can we draw a line parallel to the X-axis at a distance of 6 unIts from It and below the X-axis? ii. Will all of the points (-3,-6), (10,-6), ( , -6) be on that line? iii. What would be the equation of this line?(Textbook pg. no. 94)
Solution & Step-by-Step Answer:
i. Yes. This line will pass through the point (0,-6).

ii. Yes.
Here, y co-ordinate of the points (-3, -6), (10,-6), ( , -6) is the same, which is -6.
∴ All the above points lie on the same line.

iii. Since, the line is at a distance of 6 units below the X-axis.
∴ b = -6
∴ Equation of the line is y = -6.

Question 2 Maharashtra Board Solution
i. Can we draw a line parallel to the Y – axis at a distance of 2 units from ¡t and to its right? ii. Will all of the points (2, 10), (2, 8), (2, -) be on that line? iii. What would be the equation of this line? (Textbook pg. no. 95)
Solution & Step-by-Step Answer:
i. Yes. (2, 10) This line will pass through the point (2, 0). (2,8) ii. Yes. Here, x co-ordinate of the points (2, 10), (2, 8), (2,- ) is the same, which is 2. ∴ All the above points lie on the same line.

iii. Since, the line is at a distance of 2 units to the right of Y-axis.
a = 2
∴ Equation of the line is x = 2.

Question 3 Maharashtra Board Solution
On a graph paper, plot the points (0, 1), (1, 3), (2, 5). Are they collinear? If so, draw the line that passes through them. i. Through which quadrants does this line pass ? ii. Write the co-ordinates of the point at which it intersects the Y-axis. iii. Show any point in the third quadrant which lies on this line. Write the co-ordinates of the point. (Textbook pg. no. 96)
Solution & Step-by-Step Answer:
i. The line passes through the quadrants I, II and III. ii. The line intersects the Y-axis at (0, 1). iii. (-1,-1)