Practice Set 9.1 Geometry 9th Std Maths Part 2 Answers Chapter 9 Surface Area and Volume
Solution & Step-by-Step Answer:
i. Surface area of vertical faces of the box = 2(l + b) x h = 2(20+ 12) x 10 = 2 x 32 x 10 = 640 sq.cm.
ii. Total surface area of the box
= 2 (lb + bh + lh)
= 2(20 x 12+ 12 x 10 + 20 x 10)
= 2(240 + 120 + 200)
= 2 x 560
= 1120 sq.cm.
∴ The surface area of vertical faces and total surface area of the box are 640 sq.cm, and 1120 sq.cm, respectively.
Solution & Step-by-Step Answer:
Total surface area of the box = 2 (lb + bh + lh) ∴ 500 = 2 (6l + 6 x 5 + 5l) ∴ = (11l + 30) ∴ 250= 11l + 30 ∴ 250 – 30= 11l ∴ 220 = 11l ∴ 220 = l ∴ = l ∴ l = 20 units ∴ The length of the box is 20 units.
Solution & Step-by-Step Answer:
i. Area of vertical faces of cube = 4l2 = 4 (4.5)2 = 4 x 20.25 = 81 sq.cm. ii. Total surface area of the cube = 6l2 = 6 (4.5)2 = 6 x 20.25 = 121.5 sq.cm. ∴ The surface area of all vertical faces and the total surface area of the cube are 81 sq.cm, and 121.5 sq.cm, respectively.
Solution & Step-by-Step Answer:
i. Total surface area of cube = 6l2 ∴ 5400 = 6l2 ∴ = l2 ∴ l2 = 900 ii. Area of vertical faces of cube = 4l2 = 4 x 900 = 3600 sq.cm. ∴ The surface area of all vertical faces of the cube is 3600 sq.cm.
Solution & Step-by-Step Answer:
Volume of cuboid = l x b x h ∴ 34.50 = l x b x h ∴ 34.50 = l x 1.5 x 1.15 = 20 ∴ The length of the cuboid is 20 m.
Solution & Step-by-Step Answer:
Volume of a cube = l2 = (7.5)3 = 421.875 ≈ 421.88 cubic cm ∴The volume of the cube is 421.88 cubic cm.
Solution & Step-by-Step Answer:
i. Curved surface area of cylinder = 2πrh = 2 x 3.14 x 20 x 13 = 1632.8 sq.cm
ii. Total surface area of cylinder = 2πr(r + h)
= 2 x 3.14 x 20(20 + 13)
= 2 x 3.14 x 20 x 33 = 4144.8 sq.cm
∴ The curved surface area and the total surface area of the cylinder are 1632.8 sq.cm and 4144.8 sq.cm respectively.
Solution & Step-by-Step Answer:
Curved surface area of cylinder = 2πrh ∴ 1980 = 2 x x 15 x h ∴ ∴ h = 21 cm ∴ The height of the cylinder is 21 cm.