Latest Maharashtra State Board (SSC & HSC) 2026-27 Syllabus Digest & Solutions Updated!
Class 11 (FYJC / HSC)Mathematics & Statistics2026-27 Syllabus

Chapter 4 Determinants and Matrices Miscellaneous Exercise 4(B) Solutions

Complete Maharashtra State Board Balbharati & Yuvakbharati textbook solutions for Chapter 4 Determinants and Matrices Miscellaneous Exercise 4(B). Step-by-step solved exercises, numerical problems, and digest answers.

35 Solved Questions43 Diagrams1712 words

Maharashtra State Board 11th Maths Solutions Chapter 4 Determinants and Matrices Miscellaneous Exercise 4(B)

(I) Select the correct option from the given alternatives.

Question 1 Maharashtra Board Solution
Given A = , I = if A – λI is a singular matrix, then ___________ (a) λ = 0 (b) λ2 – 3λ – 4 = 0 (c) λ2 + 3λ – 4 = 0 (d) λ2 – 3λ – 6 = 0
Solution & Step-by-Step Answer:
(b) λ2 – 3λ – 4 = 0 Hint:

Question 2 Maharashtra Board Solution
Consider the matrices A = , B = , C = . Out of the given matrix products, ___________ (i) (AB)TC (ii) CTC(AB)T (iii) CTAB (iv) ATABBTC (a) Exactly one is defined (b) Exactly two are defined (c) Exactly three are defined (d) all four are defined
Solution & Step-by-Step Answer:
(c) Exactly three are defined Hint: A is of order 3 × 3, B is of order 3 × 2 and C is of order 3 × 1. (AB)TC is of order 2 × 1. CTC and (AB)T are of different orders. CTC (AB)T is not defined. CTAB is of order 1 × 2. ATABBTC is of order 3 × 1.
Question 3 Maharashtra Board Solution
If A and B are square matrices of equal order, then which one is correct among the following? (a) A + B = B + A (b) A + B = A – B (c) A – B = B – A (d) AB = BA
Solution & Step-by-Step Answer:
(a) A + B = B + A Hint: Matrix addition is commutative. ∴ A + B = B + A
Question 4 Maharashtra Board Solution
If A = is a matrix satisfying the equation AAT = 9I, where I is the identity matrix of order 3, then the ordered pair (a, b) is equal to ___________ (a) (2, -1) (b) (-2, 1) (c) (2, 1) (d) (-2, -1)
Solution & Step-by-Step Answer:
(d) (-2, -1)
Question 5 Maharashtra Board Solution
If A = and |A3| = 125, then α = ___________ (a) ±3 (b) ±2 (c) ±5 (d) 0
Solution & Step-by-Step Answer:
(a) ±3 Hint: |A3| = 125 |A|3 = 53 …….[∵ |An| = |A|n, n ∈ N] ∴ |A| = 5 α2 – 4 = 5 α2 = 9 ∴ α = ± 3
Question 6 Maharashtra Board Solution
If , then ___________ (a) x = 1, y = -2 (b) x = -1, y = 2 (c) x = 1, y = 2 (d) x = -1, y = -2
Solution & Step-by-Step Answer:
(c) x = 1, y = 2
Question 7 Maharashtra Board Solution
If A + B = and A – B = , then the value of A is ___________ (a) (b) (c) (d)
Solution & Step-by-Step Answer:
(b)
Question 8 Maharashtra Board Solution
If , then ___________ (a) x = 3, y = 7, z = 1, w = 14 (b) x = 3, y = -5, z = -1, w = -4 (c) x = 3, y = 6, z = 2, w = 7 (d) x = -3, y = -7, z = -1, w = -14
Solution & Step-by-Step Answer:
(a) x = 3, y = 7, z = 1, w = 14
Question 9 Maharashtra Board Solution
For suitable matrices A, B, the false statement is ___________ (a) (AB)T = ATBT (B) (AT)T = A (C) (A – B)T = AT – BT (D) (A + B)T = AT + BT
Solution & Step-by-Step Answer:
(a) (AB)T = ATBT Hint: (AB)T = BTAT
Question 10 Maharashtra Board Solution
If A = and f(x) = 2x2 – 3x, then f(A) = ___________ (a) (b) (c) (d)
Solution & Step-by-Step Answer:
(c) Hint:

(II) Answer the following questions.

Question 1 Maharashtra Board Solution
If A = diag[2, -3, -5], B = diag[4, -6, -3] and C = diag [-3, 4, 1], then find i. B + C – A ii. 2A + B – 5C.
Solution & Step-by-Step Answer:

Question 2 Maharashtra Board Solution
If f(α) = A = , find i. f(-α) ii. f(-α) + f(α)
Solution & Step-by-Step Answer:

Question 3 Maharashtra Board Solution
Find matrices A and B, where (i) 2A – B = and A + 3B = (ii) 3A – B = and A + 5B =
Solution & Step-by-Step Answer:
i. Given equations are 2A – B = …….(i)

Question 4 Maharashtra Board Solution
If A = , B = , verify i. (A + 2BT)T = AT + 2B ii. (3A – 5BT)T = 3AT – 5B.
Solution & Step-by-Step Answer:

Question 5 Maharashtra Board Solution
If A = and A + AT = I, where I is a unit matrix of order 2 × 2, then find the value of α.
Solution & Step-by-Step Answer:

Question 6 Maharashtra Board Solution
If A = and B = , show that AB is singular.
Solution & Step-by-Step Answer:

Question 7 Maharashtra Board Solution
If A = , B = , show that AB and BA are both singular matrices.
Solution & Step-by-Step Answer:

Question 8 Maharashtra Board Solution
If A = , B = , show that BA = 6I.
Solution & Step-by-Step Answer:

Question 9 Maharashtra Board Solution
If A = , B = , verify that |AB| = |A|.|B|.
Solution & Step-by-Step Answer:

Question 10 Maharashtra Board Solution
If Aα = , show that Aα. Aβ = Aα+β
Solution & Step-by-Step Answer:

Question 11 Maharashtra Board Solution
If A = , B = , where ω is a complex cube root of unity, then show that AB + BA + A – 2B is a null matrix.
Solution & Step-by-Step Answer:
ω is the complex cube root of unity. ω3 = 1 ω3 – 1 = 0 (ω – 1) (ω2 + ω + 1) = 0 ω = 1 or ω2 + ω + 1 = 0 But, ω is a complex number. 1 + ω + ω2 = 0 …….(i) AB + BA + A – 2B which is a null matrix.

Question 12 Maharashtra Board Solution
If A = , show that A2 = A.
Solution & Step-by-Step Answer:

Question 13 Maharashtra Board Solution
If A = , show that A2 = I.
Solution & Step-by-Step Answer:

Question 14 Maharashtra Board Solution
If A = , show that A2 – 5A – 14I = 0.
Solution & Step-by-Step Answer:

Question 15 Maharashtra Board Solution
If A = , show that A – 4A + 3I = 0.
Solution & Step-by-Step Answer:

Question 16 Maharashtra Board Solution
If A = , B = and (A + B)(A – B) = A2 – B2, find x and y.
Solution & Step-by-Step Answer:
(A + B)(A – B) = A2 – B2 A2 – AB + BA – B2 = A2 – B2 -AB + BA = 0 AB = BA By equality of matrices, we get 2 – 4x = -3x ∴ x = 2 and 2y = 2x y = x ∴ y = 2 ∴ x = 2, y = 2

Question 17 Maharashtra Board Solution
If A = and B = , show that (A + B)(A – B) ≠ A2 – B2.
Solution & Step-by-Step Answer:
We have to prove that (A + B). (A – B) ≠ A2 – B2 i.e., to prove that A(A – B) + B(A – B) ≠ A2 – B2 i.e., to prove that A2 – AB + BA – B2 ≠ A2 – B2 i.e., to prove that AB ≠ BA. ∴ AB ≠ BA

Question 18 Maharashtra Board Solution
If A = , find A3.
Solution & Step-by-Step Answer:
∴ A2 = I Multiplying throughout by A, we get A3 = A. I ∴ A3 = A

Question 19 Maharashtra Board Solution
Find x, y if,
Solution & Step-by-Step Answer:

Question 20 Maharashtra Board Solution
Find x, y, z if
Solution & Step-by-Step Answer:

Question 21 Maharashtra Board Solution
If A = , B = , find ABT and ATB.
Solution & Step-by-Step Answer:

Question 22 Maharashtra Board Solution
If A = , B = , show that (AB)T = BTAT.
Solution & Step-by-Step Answer:

Question 23 Maharashtra Board Solution
If A = , prove that An = , for all n ∈ N.
Solution & Step-by-Step Answer:

Question 24 Maharashtra Board Solution
If A = , prove that An = , for all n ∈ N.
Solution & Step-by-Step Answer:

Question 25 Maharashtra Board Solution
Two farmers Shantaram and Kantaram cultivate three crops rice, wheat, and groundnut. The sale (in Rupees) of these crops by both the farmers for the month of April and may 2008 is given below, Find (i) the total sale in rupees for two months of each farmer for each crop. (ii) the increase in sales from April to May for every crop of each farmer.
Solution & Step-by-Step Answer:
(i) Total sale for Shantaram: For rice = 15000 + 18000 = ₹ 33000. For wheat = 13000 + 15000 = ₹ 28000. For groundnut = 12000 + 12000 = ₹ 24000. Total sale for Kantaram: For rice = 18000 + 21000 = ₹ 39000 For wheat = 15000 + 16500 = ₹ 31500 For groundnut = 8000 + 16000 = ₹ 24000

Alternate method:
Matrix form

∴ The total sale of April and May of Shantaram in ₹ is ₹ 33000 (rice), ₹ 28000 (wheat), ₹ 24000 (groundnut), and that of Kantaram in ₹ is ₹ 39000(rice), ₹ 31500(wheat), and ₹ 24000 (groundnut).

(ii) Increase in sale from April to May for Shantaram:
For rice = 18000 – 15000 = ₹ 3000
For wheat = 15000 – 13000 = ₹ 2000
For groundnut = 12000 – 12000 = ₹ 0
Increase in sale from April to May for Kantaram:
For rice = 21000 – 18000 = ₹ 3000
For wheat = 16500 – 15000 = ₹ 1500
For groundnut = 16000 – 8000 = ₹ 8000

Alternate method:
Matrix form

∴ The increase in sales for Shantaram from April to May in each crop is ₹ 3000 (rice), ₹ 2000(wheat), 0 (groundnut), and that for Kantaram is ₹ 3000 (rice), ₹ 1500 (wheat), and ₹ 8000 (groundnut).