Chapter 1 Differentiation Ex 1.4
Chapter 1 Differentiation Ex 1.4
Differentiating x and y w.r.t. t, we get
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-2.jpeg)
(ii) x = a cot θ, y = b cosec θ
Solution:
x = a cot θ, y = b cosec θ
Differentiating x and y w.r.t. θ, we get
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-4.png)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-5.jpeg)
(iv) x = sin θ, y = tan θ
Solution:
x = sin θ, y = tan θ
Differentiating x and y w.r.t. θ, we get
(v) x = a(1 – cos θ), y = b(θ – sin θ)
Solution:
x = a(1 – cos θ), y = b(θ – sin θ)
Differentiating x and y w.r.t. θ, we get
Differentiating x and y w.r.t. t, we get
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-11.png)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-12.jpeg)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-13.jpeg)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-14.png)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-15.jpeg)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-16.jpeg)
Differentiating x and y w.r.t. θ, we get
Differentiating x and y w.r.t. θ, we get
Differentiating x and y w.r.t. t, we get
(iv) x = 2 cos t + cos 2t, y = 2 sin t – sin 2t at t =
Solution:
x = 2 cos t + cos 2t, y = 2 sin t – sin 2t
Differentiating x and y w.r.t. t, we get
(v) x = t + 2 sin(πt), y = 3t – cos(πt) at t =
Solution:
x = t + 2 sin(πt), y = 3t – cos(πt)
Differentiating x and y w.r.t. t, we get
Question 3.
log x = (sin 3t)(log e), log y = (cos 3t)(log e)
log x = sin 3t, log y = cos 3t ….. (1) [∵ log e = 1]
Differentiating both sides w.r.t. t, we get
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-32.png)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-33.jpeg)
![Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (iii).1](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/maharashtra-board-12th-maths-solutions-chapter-1-d-354.png)
Differentiating x and y w.r.t. t, we get
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-39.png)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-40.jpeg)
Differentiating x and y w.r.t. t, we get
Differentiating x and y w.r.t. t, we get
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-47.png)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-48.jpeg)
Question 4.
(i) Differentiate x sin x w.r.t tan x.
Solution:
Let u = x sinx and v = tan x
Then we want to find
Differentiating u and v w.r.t. x, we get
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-50.png)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-51.jpeg)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-52.jpeg)
Solution:
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-56.png)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-57.jpeg)
(v) Differentiate 3x w.r.t. logx3.
Solution:
Differentiating u and v w.r.t. x, we get
Differentiating both sides w.r.t. x, we get
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-66.png)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-67.jpeg)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-68.jpeg)
![](https://mhboardsolutions.xyz/wp-content/uploads/2022/02/word-image-19650-69.jpeg)