Chapter 1 Differentiation Ex 1.5

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Chapter 1 Differentiation Ex 1.5

Chapter 1 Differentiation Ex 1.5

Question 1.
Find the second order derivatives of the following:



(ii)  . tan x
Solution:
Let y =  . tan x


(iii)   . cos 5x
Solution:
Let y =   . cos 5x

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q1 (iii)

(iv)  . log x
Solution:
Let y =  . log x

(v) log(log x)
Solution:
Let y = log(log x)

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q1 (v)

(vi)
Solution:
y =

log y = log  = x log x
Differentiating both sides w.r.t. x, we get

Question 2.

(ii) x = 2a, y = 4at
Solution:
x = 2a, y = 4at

Differentiating x and y w.r.t. t, we get


Solution:
x = sin θ, y = θ

Differentiating x and y w.r.t. θ, we get,


Solution:
x = a cos θ, y = b sin θ

Differentiating x and y w.r.t. θ, we get


Question 3.

Differentiating x and y w.r.t. t, we get


Solution:
y = x + tan x


Solution:



Differentiating both sides w.r.t. x, we get


Differentiating both sides w.r.t. x, we get

(x) If y = log(log 2x), show that x + (1 + x) = 0.
Solution:
y = log(log 2x)

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q3 (x)


Differentiating both sides w.r.t. x, we get



Solution:
x = a sin t – b cos t, y = a cos t + b sin t
Differentiating x and y w.r.t. t, we get

Question 4.
Find the nth derivative of the following:
(i) (ax +
Solution:

Let y = (ax +


(ii)  1/x
Solution:
Let y = 1/x

(iii)
Solution:
Let y =

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q4 (iii)

(iv)
Solution:
Let y =

(v) log(ax + b)
Solution:

Let y = log(ax + b)

(vi) cos x
Solution:
Let y = cos x

(vii) sin(ax + b)
Solution:
Let y = sin(ax + b)


(viii) cos(3 – 2x)
Solution:

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q4 (viii)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q4 (viii).1

(ix) log(2x + 3)
Solution:

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q4 (ix)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q4 (ix).1

(xi) y =  . cos (bx + c)
Solution:
y =  . cos (bx + c)





(xii) y =  . cos (6x + 7)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q4 (xii)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q4 (xii).1
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q4 (xii).2
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.5 Q4 (xii).3