Chapter 11 Statistics Set 11.2

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Chapter 11 Statistics Set 11.2

Question 1.
Observe the following graph and answer the questions.
Maharashtra Board Class 8 Maths Solutions Chapter 11 Statistics Practice Set 11.2 1


i. State the type of the graph.
ii. How much is the savings of Vaishali in the month of April?
iii. How much is the total of savings of Saroj in the months March and April?
iv. How much more is the total savings of Savita than the total savings of Megha?
v. Whose savings in the month of April is the least?
Solution:
i. The given graph is a subdivided bar graph.
ii. Vaishali’s savings in the month of April is Rs 600.
iii. Total savings of Saroj in the months of March and April is Rs 800.
iv. Savita’s total saving = Rs 1000, Megha’s total saving = Rs 500
∴ difference in their savings = 1000 – 500 = Rs 500.
Savita’s saving is Rs 500 more than Megha.
v. Megha’s savings in the month of April is the least.

Question 2.
The number of boys and girls, in std 5 to std 8 in a Z.P. School is given in the table. Draw a subdivided bar graph to show the data. (Scale : On Y axis, 1cm = 10 students)

Standard

5th

6th

7th

8th

Boys

34

26

21

25

Girls

17

14

14

20

Solution:

Standard

5th

6th

7th

8th

Boys

34

26

21

25

Girls

17

14

14

20

Total

51

40

35

45

Maharashtra Board Class 8 Maths Solutions Chapter 11 Statistics Practice Set 11.2 2

Question 3.
In the following table number of trees planted in the year 2016 and 2017 in four towns is given. Show the data with the help of subdivided bar graph.

Year\Town

karjat

Wadgaon

Shivapur

Khandala

2016

150

250

200

100

2017

200

300

250

150

Solution:

Year\Town

karjat

Wadgaon

Shivapur

Khandala

2016

150

250

200

100

2017

200

300

250

150

Total

350

550

450

250

Maharashtra Board Class 8 Maths Solutions Chapter 11 Statistics Practice Set 11.2 3

Question 4.
In the following table, data of the transport means used by students in 8th standard for commutation between home and school is given. Draw a subdivided bar diagram to show the data.
(Scale: On Y axis: 1 cm = 500 students)

Means of commutation\Town

Paithan

Yeola

Shahapur

Cycle

3250

1500

1250

Bus and auto

750

500

500

On foot

1000

1000

500

Solution:

Means of commutation\Town

Paithan

Yeola

Shahapur

Cycle

3250

1500

1250

Bus and auto

750

500

500

On foot

1000

1000

500

Total

5000

3000

2250

Maharashtra Board Class 8 Maths Solutions Chapter 11 Statistics Practice Set 11.2 4