## Chapter 15 Area Set 15.6

iii. Radius of the circle (r) = 17.5 cm … [Given]

Area of the circle = πr²

= x(17.5)²

= x 17.5 x 17.5

= 22 x 2.5 x 17.5

= 962.5 sq. cm

Question 2.

Areas of some circles are given below, find their diameters.

i. 176 sq.cm

ii. 394.24 sq. cm

iii. 12474 sq. cm

Solution:

i. Area of the circle =176 sq. cm .. .[Given]

Area of the circle = πr²

∴ 176 = 22/7 x r²

∴ r² = 176 x

∴ r² = 56

∴ r = √56 … [Taking square root of both sides]

Diameter = 2r = 2√56 CM

ii. Area of the circle = 394.24 sq. cm … [Given]

Area of the circle = πr²

∴ Diameter = 2r = 2 x 11.2 = 22.4 cm

Question 3.

Diameter of the circular garden is 42 m. There is a 3.5 m wide road around the garden. Find the area of the road.

Solution:

Diameter of the circular garden is 42 m. … [Given]

∴ Radius of the circular garden (r) = 42/2 = 21 m

Width of the road = 3.5 m …[Given]

Radius of the outer circle (R)

= radius (r) + width of the road

= 21 + 3.5

= 24.5 m

Area of the road = area of outer circle – area of circular garden

= πR² – πr²

= π (R² – r²)

= [(24.5)² – (21)²]

= (24.5 + 21) (24.5 – 21)

…..[∵ a²-b² = (a+b)(a-b)]

= 227 x 45.5 x 3.5

= 22 x 45.5 x 0.5

= 500.50 sq. m

∴ The area of the road is 500.50 sq. m.

**Intext Questions and Activities**

Question 1.

Draw a circle of radius 28mm. Draw any one triangle and draw a trapezium on the graph paper. Find the area of these figures by counting the number of small squares on the graph paper. Verify your answers using formula for area of these figures.

Observe that smaller the squares of graph paper, better is the approximation of area. (Textbook pg. no. 105)

Solution:

(Students should do this activity on their own.)